(8x-1)(x^2-4x+1)=0

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Solution for (8x-1)(x^2-4x+1)=0 equation: 


Simplifying
(8x + -1)(x2 + -4x + 1) = 0

Reorder the terms:
(-1 + 8x)(x2 + -4x + 1) = 0

Reorder the terms:
(-1 + 8x)(1 + -4x + x2) = 0

Multiply (-1 + 8x) * (1 + -4x + x2)
(-1(1 + -4x + x2) + 8x * (1 + -4x + x2)) = 0
((1 * -1 + -4x * -1 + x2 * -1) + 8x * (1 + -4x + x2)) = 0
((-1 + 4x + -1x2) + 8x * (1 + -4x + x2)) = 0
(-1 + 4x + -1x2 + (1 * 8x + -4x * 8x + x2 * 8x)) = 0
(-1 + 4x + -1x2 + (8x + -32x2 + 8x3)) = 0

Reorder the terms:
(-1 + 4x + 8x + -1x2 + -32x2 + 8x3) = 0

Combine like terms: 4x + 8x = 12x
(-1 + 12x + -1x2 + -32x2 + 8x3) = 0

Combine like terms: -1x2 + -32x2 = -33x2
(-1 + 12x + -33x2 + 8x3) = 0

Solving
-1 + 12x + -33x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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